Question

Did I write this proof correctly? Details below.

Answer 1

Show that if A is nxn with n odd and skew symmetric, then det(A) = 0

Given: Matrix A is an nxn matrix and it's skew symmetric.
n is an odd integer
The result is det(A)= 0

Answer 2

First, we need to go back to the previous problem before we can prove this statement.

Show that if k is a scalar and A is nxn, then det(kA)= k^n det(A)


Definition 3.2 states that if A = [aij] is an nxn matrix, then the determinant is defined by