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Simplify the equation: ((a-b)(a+b)) / ((b-a)(b-a))
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Hint: b-a = -a + b = -(a - b)
b-a = -(a - b) so (b-a)(b-a) = [ -(a-b) ][ -(a-b) ] (b-a)(b-a) = (-1)*(-1)*(a-b)(a-b) (b-a)(b-a) = 1*(a-b)(a-b) (b-a)(b-a) = (a-b)(a-b)
That means \[\Large \frac{(a-b)(a+b)}{(b-a)(b-a)}\] turns into \[\Large \frac{(a-b)(a+b)}{(a-b)(a-b)}\]
OH! That makes so much more sense. Thank you so much.
I'm sure you see what to do from here. What do you get?
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You get \[\frac{ a+b }{ a-b }\] right?
very good, a pair of (a-b) terms cancel out
Thank you!
you're welcome
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