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Mathematics 7 Online
OpenStudy (anonymous):

Simplify the equation: ((a-b)(a+b)) / ((b-a)(b-a))

jimthompson5910 (jim_thompson5910):

Hint: b-a = -a + b = -(a - b)

jimthompson5910 (jim_thompson5910):

b-a = -(a - b) so (b-a)(b-a) = [ -(a-b) ][ -(a-b) ] (b-a)(b-a) = (-1)*(-1)*(a-b)(a-b) (b-a)(b-a) = 1*(a-b)(a-b) (b-a)(b-a) = (a-b)(a-b)

jimthompson5910 (jim_thompson5910):

That means \[\Large \frac{(a-b)(a+b)}{(b-a)(b-a)}\] turns into \[\Large \frac{(a-b)(a+b)}{(a-b)(a-b)}\]

OpenStudy (anonymous):

OH! That makes so much more sense. Thank you so much.

jimthompson5910 (jim_thompson5910):

I'm sure you see what to do from here. What do you get?

OpenStudy (anonymous):

You get \[\frac{ a+b }{ a-b }\] right?

jimthompson5910 (jim_thompson5910):

very good, a pair of (a-b) terms cancel out

OpenStudy (anonymous):

Thank you!

jimthompson5910 (jim_thompson5910):

you're welcome

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