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OpenStudy (anonymous):

Could you please help me.

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OpenStudy (anonymous):

\[(\frac{ 1 }{ e })^{-x}=(\frac{ 1 }{ e ^{2} })^{x+1}\]

OpenStudy (anonymous):

\[(\frac{1}{e})^{-x}=(\frac{1}{e})^{2x+2}\] since bases are same, powers must be same

OpenStudy (anonymous):

So how do I do that?

OpenStudy (anonymous):

-x=2x+2

OpenStudy (anonymous):

Ok thank you! Man, I totally forgot how to do this stuff -_-

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