Question

Could you please help me.

Answer 1

\[(\frac{ 1 }{ e })^{-x}=(\frac{ 1 }{ e ^{2} })^{x+1}\]

Answer 2

\[(\frac{1}{e})^{-x}=(\frac{1}{e})^{2x+2}\]
since bases are same, powers must be same

Answer 3

So how do I do that?

Answer 4

-x=2x+2

Answer 5

Ok thank you! Man, I totally forgot how to do this stuff -_-