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Mathematics 22 Online
OpenStudy (anonymous):

Let S ={1, 2, 3, 4, 5, 6, 7}, E ={1, 3, 5, 7}, F ={7, 4, 6}, G ={1, 4}. Find (a) EF ; (b) E ∪ FG (c) EG' (d) EF'∪G (e) E'(F ∪ G) (f ) EG ∪FG.

OpenStudy (anonymous):

are you suppose to use a matrix?

OpenStudy (anonymous):

Nop. @Hope_nicole The normal Ven Diagram one I guess.

OpenStudy (anonymous):

Ummmm...what do you mean? i have never heard of using a ven diagram in math..

OpenStudy (anonymous):

@Hope_nicole Confused I am, any idea on this?

OpenStudy (anonymous):

well, the EF means they want you to multiply them so i guess you would multiply them all together? are there any options for it?

OpenStudy (anonymous):

as far as I know, EF is only 7, the common one.

OpenStudy (anonymous):

how in the world?! im sorry i have no idea. :/

OpenStudy (anonymous):

@ParthKohli Hello! Could you help me out with this? :( Great help it would be :)

Parth (parthkohli):

Is \(EF = E \times F\)?

OpenStudy (anonymous):

yes..E ∩F

Parth (parthkohli):

Oh, the intersection. You're right... it is \(7\).

Parth (parthkohli):

The second is \(E \cup F \cap G\), right?

OpenStudy (anonymous):

yes!

Parth (parthkohli):

OK, assume that you are going from left to right.

Parth (parthkohli):

Can you do it?

OpenStudy (anonymous):

So is it, 1,3,4,5,7 ?

OpenStudy (anonymous):

I am actually confused with c) @ParthKohli

Parth (parthkohli):

Oh.

Parth (parthkohli):

\[E \cup G'\]What are the elements that are not in \(G\), but occur at least once in other sets?

OpenStudy (anonymous):

isn't it E ∩ G′ ??

OpenStudy (anonymous):

the answer to your question would be 4!

Parth (parthkohli):

hmm.

Parth (parthkohli):

Sorry, yes.

Parth (parthkohli):

{3,5,7} is the required set.

OpenStudy (anonymous):

shouldn't 4 be included as well? {3,4,5,7}

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