Question

Probability

Answer 1

The following five games are scheduled to be played at the World curling championship one morning. The values in parentheses are the probabilities of each team winning their respective game.

Game 1: Finland vs Germany
Game 2:USA vs Switzerland
Game3:Japan vs Canada
Game4:Denmark vs Sweden
Game 5:France vs Scotland

The outcome of interest is the winners of the five games.how many out comes are contained in the sample space?

Answer 2

the answer is 5.

Answer 3

No answer is 32

Answer 4

But I don't know how

Answer 5

there are no paranthesised values

Answer 6

0.43 vs 0.57
0.28vs 0.72
0.11vs 0.89
0.33vs o.67
0.18vs 0.82

Answer 7

assuming each game can only have one winner ... and he outcome of interest is the winners of the five games.

a.b -> a
c.d -> c
e.f -> e
g.h -> g
i .j -> i

which leads one to believe that the set of outcomes has a cardinality of 5

is there something else to the setup that we might be overlooking?

Answer 8

But the answer is 32

Answer 9

it might be asking, of the 10 teams, how many ways are there to choose 5 winners?

(10P5)/5!

10.9.8.7.6
-----------
5.4.3.2


2.9.7.2 ; .... is greater than 32 so its not that

Answer 10

What is the probability that at least one underdog wins?

Answer 11

Underdog is the team who is less likely to win

Answer 12

i dont know the rules of how winners are paired up with losers ... so i cant even begin to make an educated run at this

Answer 13

you have 5 teams in the running, 4 teams get paired up with a 1 team in the wings .... to do what? there is either assumed knowledge that is not present, or missing information that i cant deduce.

Answer 14

The favourite is the team with the higher probability of winning

Answer 15

Underdog is the team who is less likely to win

Answer 16

What is the probability that at least one underdog wins?

Answer 17

That's what all the question asking about

Answer 18

thats doesnt really help me out in determining anything past the first round of winners and losers

Answer 19

in any case, this question makes no sense to me so im not going to be of any use in solving it .... good luck

Answer 20

I have included the relevant numbers for each team

Answer 21

yes you have, and they still dont help me sort anything out ....

Answer 22

Tomo help me

Answer 23

C(2,1)*C(2,1)*C(2,1)*C(2,1)*C(2,1) = 2^5 = 32

Answer 24

What is the probability that at least one underdog wins?

Answer 25

1-P(no underdog wins)

Answer 26

What are the non underdog wins?

Answer 27

it almost sounds like a decision tree model

http://www.bus.utk.edu/stat/datamining/Decision%20Trees%20for%20Predictive%20Modeling%20(Neville).pdf

Answer 28

i see the 32 from 5 cases in there

Answer 29

Game 1: Finland vs Germany
Game 2:USA vs Switzerland
Game3:Japan vs Canada
Game4:Denmark vs Sweden
Game 5:France vs Scotland

0.43 vs 0.57
0.28 vs 0.72
0.11 vs 0.89
0.33 vs 0.67
0.18 vs 0.82


since they are independent P(A AND B) = P(A)*P(B) you want



1-[P(germany wins AND switzerland wins AND canda wins AND sweden wins AND scotland wins)]

= 1-P(germany wins)*P(switzerland wins) *P(canada wins) * P(sweden wins) * P(scotland wins)

= 1-(.57*.72*.89*.67*.82)

= 0.7993283536

Answer 30

Each game has 2 possible outcomes. The sample space is 2^5 = 32

Answer 31

I see thank you very much tomo

Answer 32

your welcome