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f(x)=8x√x+3 Find the domain of the function
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the domain will contain values, for which the quantity under \(\sqrt{....} \) will be positive. so, here, if x+3 >0 what can you say about 'x' ?
@warsop87 just like the last one, only with \(x+3\geq 0\) instead of \(x-3\geq 0\)
It told me that was wrong it said the right answer was the infinity sign and 3 so I am confused now
\[x-3\geq 0\iff x\geq 3\] in interval notation this is \[[3,\infty)\]
it is just a different notation, interval notation rather than inequality notation
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ohhhh ok
for this, \([-3,\infty)\)
for example \[-2<x\leq 7\] vs \[(-2,7]\]
thank you so much
you are welcome ^_^
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