Question

I'm already stuck on this problem

What is the 7th term of the geometric sequence where a1 = 625 and a2 = -125?

First term: 625

Answer 1

common ratio = a2/a1 =.. ?

Answer 2

-125/625

Answer 3

= -5

Answer 4

thats your 'r'
a1 =625
we want 7th term, so n=7

Answer 5

-5, sure ? check again ....

Answer 6

dont tell m the answer yet!!!!!!

Answer 7

me*

Answer 8

-0.2

Answer 9

R = -0.2

Answer 10

r= -0.2 or -1/5 is correct.
now use the formula

Answer 11

ok!! no answers yet please

Answer 12

0.04000000000000002

Answer 13

in other words: (or numbers) 0.04?

Answer 14

The formula for the nth term in a Geometric sqeuence:
\[a_n=a_1r^{n-1}\]
Plugging in \(a_1=625\) we have
\[a_n=625r^{n-1}\]
For the second \((n=2)\) term of the sequence we have \(a_2=-125\). Lets plug \(a_2\)
\[a_2=625r^{2-1} \rightarrow-125=625r^1\]
We now have \(r\)!

Answer 15

0.04 is correct :)
no point in writing so many zero's :P

Answer 16

oh my gosh i did it all by myself!!!! thank you for your help....you taught me well!!!!

Answer 17

*applauses*

Answer 18

thank you thank you!!!!!!

Answer 19

welcome welcome!!!!!!