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Find the standard form for the equation of a circle (x−h)2+(y−k)2=r2 with a diameter that has endpoints (−8,6) and (9,−8)
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Use the distance formula to find the diameter.
Then use the midpoint formula to find the center of the circle.
sqrt((9-(-8))^2(((-8)-6)^2)=238
(1/2,-1)=midpoint
\[\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^2}=d\]
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The midpoint is correct.
what about the distance formula
\[\sqrt{(-8-9)^2+(6+8)^2}=d=\sqrt{289+196}=\sqrt{485}=r\]
So r^2=485
And now you can write the equation of the circle because you know h, k and r^2
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oh ok i see what i did wrong thank you
yw
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