Question

How many grams of CaSO4 are needed to prepare an 875 mL solution with a concentration of 2.0 M ?

Answer 1

do you need the number or the solution?

Answer 2

Molar mass of CaSO4 = 136.1406 g/mol

\[875 ml \times \frac{ 2 mole }{ 1 liter } = 1750 mmol\] of CaSO4
now
\[1750 mmol \times \frac{ 136 gram }{ 1 mol } = 238 grams\] of CaSO4