Question

can someone solve this problem... ? probability word problem..:/



A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the probability that during a randomly selected hour, the organization will receive fewer than two calls.
Answer choices>>>>>

0.106

0.087

0.317

0.894

Answer 1

Do you have a TI calculator with you?

Answer 2

no i just have a regular one ;/

Answer 3

ok there's an alternative

http://www.danielsoper.com/statcalc3/calc.aspx?id=80

if you type 1 in the first box and type 0.55 in the second box, then hit calculate, what do you get?

Answer 4

i got 0.89427221

Answer 5

omg awesome thank youuuu:)

Answer 6

thats it ? that was too easy lol

Answer 7

you got it

Answer 8

that's a very specialized calculator for computing poisson distribution cdf values, so save it for later (if you need to do any more cdf values for a poisson distribution)

Answer 9

there are other specialized calculators if you click on the "Related Calculators" button

Answer 10

wow thanks :)

Answer 11

you're welcome