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OpenStudy (anonymous):
@jim_thompson5910 @phi
OpenStudy (anonymous):
what's up?
OpenStudy (anonymous):
What are the mean, variance, and standard deviation of these values? Round to the nearest tenth.
OpenStudy (anonymous):
@Directrix
jimthompson5910 (jim_thompson5910):
Let's find the mean first
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jimthompson5910 (jim_thompson5910):
how do we do this?
OpenStudy (anonymous):
the mean is 47.6
jimthompson5910 (jim_thompson5910):
good, add them up and divide by 5
jimthompson5910 (jim_thompson5910):
how about the variance?
OpenStudy (anonymous):
31?
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jimthompson5910 (jim_thompson5910):
I think they want us to find the sample variance
jimthompson5910 (jim_thompson5910):
so you would add up the values in the last column
then divide by 4 (one less than the number of items)
OpenStudy (anonymous):
so would it be 65.3
jimthompson5910 (jim_thompson5910):
ad them up to get: 29.2+11.6+0.2+2+112.4 = 155.4
OpenStudy (anonymous):
yes and you get 31
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jimthompson5910 (jim_thompson5910):
then divide by 4 to get 155.4/4 = 38.85
OpenStudy (anonymous):
38.85 isnt on my answer choice.
OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
ok so they probably want the population variance
jimthompson5910 (jim_thompson5910):
155.4/5 = 31.08
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OpenStudy (anonymous):
Thats my answer choice. And this is the problem iv been stuck on since 4pm
jimthompson5910 (jim_thompson5910):
close enough to 31 i guess
OpenStudy (anonymous):
its 11:29pm lol
OpenStudy (anonymous):
True. So is my SD 5.6 ?
jimthompson5910 (jim_thompson5910):
then take the square root of 31 to get sqrt(31) = 5.56776436283002
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jimthompson5910 (jim_thompson5910):
yep, that rounds to 5.6
OpenStudy (anonymous):
So that means my answer is A ?
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
Susan keeps track of the number of tickets sold for each play presented at the community theater. Within how many standard deviations of the mean do all the values fall?
135, 71, 69, 80, 158, 152, 161, 96, 122, 118, 87, 85
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OpenStudy (anonymous):
Is my answer 2 ?
jimthompson5910 (jim_thompson5910):
one sec
jimthompson5910 (jim_thompson5910):
I'm assuming you have answer choices here as well?
OpenStudy (anonymous):
huh ?
jimthompson5910 (jim_thompson5910):
is this a multiple choice question?
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OpenStudy (anonymous):
A)3
B)4
C)5
D)2
jimthompson5910 (jim_thompson5910):
like the last one
jimthompson5910 (jim_thompson5910):
ok thx
OpenStudy (anonymous):
Is my answer 2?
jimthompson5910 (jim_thompson5910):
one sec, finding the standard deviation
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OpenStudy (anonymous):
Kk
jimthompson5910 (jim_thompson5910):
yes it's 2 since everything is within the interval (mu - 2*sigma, mu + 2*sigma)
OpenStudy (anonymous):
The graph below displays how many pieces of candy Timmy and his five friends each received last Halloween. Within how many standard deviations of the mean do the values fall?
OpenStudy (anonymous):
You there ?
jimthompson5910 (jim_thompson5910):
yeah trying to work it out
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OpenStudy (anonymous):
K
jimthompson5910 (jim_thompson5910):
this is another 2 as well, for the same reasons
OpenStudy (anonymous):
Thank you. Is 2 my answer
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
Thank you
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jimthompson5910 (jim_thompson5910):
yw
OpenStudy (cagliero423):
These are all correct (And the first answer on this quiz, which isn't on this post, is B)
OpenStudy (omarbirjas):
@cagliero423 OS needs more ppl like you....whats the last one tho? number 4