Help? For this circle, a 70 degree central angle cut off an arc of 8 in. What is the circumference of the circle?
\[\theta = arc/radius\]
Hint: angle must be in Radian
After finding the radius Circum..... = 2 pie r
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@Yahoo! What's radian?
it is a kind of way to measure angle
pie radian = 180 degree
For the radian I got 1.2 rad.
Then it's something like 1.2rad=8/r?
Think of 360 degrees as being analogous to 2*pi*r as the circumference of the circle. So, 70/360 = 8/(2 * pi* r) where r is the radius of the circle.
r = 144/(7*pi) To find the circumference, C = 2 * pi* r. Substitute for r and solve. C = 2 * pi* [ (144/(7*pi))]
I got 41.1
41.143 inches approx is what I got. So, we agree.
The choose was rounded. But thank you so much. I can't believe that is 6th grade math...
Sixth grade math varies. I don't know the context of the problem or how the sixth graders were taught to think about this problem.
My sister said they've never seen this before in her entire year and I'm a sophomore and I've never seen it either. Being in Algebra II I thought I had seen it before. I guess everywhere is different though.
The algebraic approach - writing and solving an equation - usually comes in a Geometry class. At least, that is where I have seen it.
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