Question

help

Answer 1

Proportions?
\(\Large\frac{36}{6} = \frac{63+x}{x+3}\)
Now I'm afraid you don't know how to do that.
So:
Solve for x over the real numbers:
\(\Large 6 = \frac{[x+63]}{[x+3]}\)
Reverse the equality in \(\Large 6 = \frac {[x+63]}{[x+3]}\) in order to isolate x to the left hand side.

\(\large 6 = \frac {[x+63]}{[x+3]}\) is equivalent to \(\large \frac {[x+63]}{[x+3]} = 6\):
\(\large \frac {[x+63]}{[x+3]} = 6\)

Multiply both sides by a polynomial to clear fractions.
Multiply both sides by \(x+3\):
\(x+63 = 6 (x+3)\)
Write the linear polynomial on the right hand side in standard form.
Expand out terms of the right hand side:
\(x+63 = 6 x+18\)
Isolate \(x\) to the left hand side.
Subtract \(6 x+63\) from both sides:
\(-5 x = -45\)
Solve for x.
Divide both sides by -5:
Answer:
\(x = 9\)

Since \(x = 9\) plug it in to check.
\(\Large\frac{36}{6} = \frac{63+9}{9+3}\)
\(\Large\frac{36}{6} = 6\)

Simplify the following::
\(\large \frac {63+9}{9+3}\)
Evaluate \(9+3\).
\(9+3 = 12\):
\(\large \frac {[63+9]}{12}\)
Evaluate \(63+9\) using long addition.
\(\large \frac {72}{12}\)
Divide 72 by 12.
\(\large \frac{72}{12} = \frac {[12×6]}{12} = 6\):
Answer:
6
Does \(6=6\)?
Yes it does \(\huge \color {red} ✔\)