Question

find the critical points: s(t)= (t-1)^4 (t+5)^3

Answer 1

first we find the derivative.. i know that.. then...?

Answer 2

then equate it to 0

Answer 3

set it = 0

Answer 4

but wait, im confused to find the derivative for this one..

Answer 5

s'(t) =0

Answer 6

chain rule/product rule

Answer 7

its 4(t-1)^3 3(t+5)^2

Answer 8

Yup

Answer 9

what's next after it? i'm a little lost after it

Answer 10

4(t-1)^3 3(t+5)^2 = 0

Answer 11

Now Find t

Answer 12

what about chain rule?

Answer 13

doesnt apply here because derviative of t is just 1

Answer 14

if ur function is of the type (t^2 + 2)^4

then s'(t) = 4 (t^2+2) * 2t

Answer 15

sorry

s'(t) = 4 (t^2+2)^3 * 2t

Answer 16

oh right.

Answer 17

so if the derivative of t is 1 then how do i solve t?

Answer 18

sorry imm not sure what to do after ... 4(t-1)^3 3(t+5)^2