How do you find the arctan of (-rad3), what is the value in degrees and in radians, how do i do it?

Question

anonymous · Answer

Do I simply input that into the calculator?

anonymous · Answer

Is it -60 degrees and pi/4 radians?

anonymous · Answer

@jim_thompson5910

jim_thompson5910 · Answer

you want $$\Large \arctan(-\sqrt{3})$$ right?

anonymous · Answer

right

jim_thompson5910 · Answer

yes you would type in arctan(-sqrt(3)) to get -60 which is the same as -pi/3

anonymous · Answer

negative?

anonymous · Answer

oh right nevermind

anonymous · Answer

That or have your unit circle memorized, which is what I require my students to do, no calculator!

anonymous · Answer

lol..I'm mean.

anonymous · Answer

Lol I've tried memorizing it, but nothing came out of it, I still can't graph the sin and cos graph...im working on it :D

anonymous · Answer

what's the density of water in newton/m^3

anonymous · Answer

You just really need to memorize the first quadrant, and then use the ASTC in QI-IV so that you can apply the appropriate signs to each of them.  in QI, all trig functions are Positive,, in QII, sine and csc are positive, in QIII, tan and cot are positive, and in QIV, cos and sec are positive.  After that, your basic 30, 45, 60 and 90 degree angles can be repeated in each of the quadrants with the appropriate signs, of course.