The lengths of the eggs of a species of bird are roughly normally distributed, with a mean of 32 mm and an SD of 1.2 mm.Approximately what is the 99th percentile of the lengths? Is it posible to have some help?Thank you

Question

directrix · Answer

To get the z-score for the 99th percentile, I use an online normal distribution table. Reading in the table from its interior out, I got z to be 2.33.

2.33 = (x - 32)/1.2  where x is the egg length at the 99th percentile position in the data.


Cross multiply and solve for x

(x - 32) = 2.33 * 1.2

directrix · Answer

I'll add a section about how to read the normal distribution area table for those like me who don't have a calculator handy.

amistre64 · Answer

hmmm, same exact question was asked by another user ...  and of course i gave a very similar answer :)

directrix · Answer

That question had the same bird data but a difference task. I think it was an interval containing 50% of the data problem.
@amistre64

directrix · Answer

How to read a z-score from a table of areas under the standard normal distribution curve.

directrix · Answer

http://openstudy.com/users/amistre64#/updates/5141bbabe4b0f08cbdc979ef

amistre64 · Answer

thats the one :)