The lengths of the eggs of a species of bird are roughly normally distributed, with a mean of 32 mm and an SD of 1.2 mm.Approximately what is the 99th percentile of the lengths? Is it posible to have some help?Thank you

Question

amistre64 · Answer

$$Z_{.9900}=\frac{x-\bar x}{sd}$$

amistre64 · Answer

therefore, solving for x we get:$$Z_{99\%}(sd)+mean=x$$

amistre64 · Answer

youll prolly need to table the Z score of 99%

anonymous · Answer

plz provide the answer

amistre64 · Answer

i did provide the answer, now its up to you to provide the work.

amistre64 · Answer

http://openstudy.com/terms-and-conditions

anonymous · Answer

my ans is 35.108 ,
but it is not the correct one.

amistre64 · Answer

what did you use or find as the Z score of 99%?

you have a table for that? or calculator?

anonymous · Answer

z99%=2.59 is it right?

amistre64 · Answer

2.59 is a z99.52%

try it with 2.33 instead, thats the closest field entry at z99.01%

anonymous · Answer

ok thanks

amistre64 · Answer

with any luck, its about 34.8 or so