H1-NMR, what molecule do you get from the following spectra?
I have been analyzing the integral and got the following ratio 2:2:3:3 from left towards right. The total number of atoms is unknown.
And I know it is a organic molecule...
do they have given empirical formula please check it out without that it is difficult LOL
It is... and I can't do a MS and UI
mean
sorry meant IR ;)
But I think that we are something in the size of ethyl 3-oxobutanoat. Almost fits but I know it is not that.
CH3CH2-O group is there what u say
CH3CH2-O-CH2-C(CH3)3 how about this
can't read around 2 (the scale is ridiculous) but both around 2 and 3 are retricemetric I would say.
The peak at 2.5 and 3 are singlet right i can say they are doublet or quatret
My original guess:
they could be singlets given the resolution of the spectrum.
But we have the specific ppm to assist so I would think it is dublets.
yaa lol!!! just missed but said that it contains CH3CH2O right
according to they are singlet only the peaks at 3.41 and 2.27
But please correct me if you guys think I'm wrong on this point, but we can read off using both numbers and the diagram that: 3 protons see 2 protons < 3 protons see 3 protons < 2 protons see 1 proton < 2 protons see 3 protons?
why don't you try it there: http://web.chemdoodle.com/demos/simulate-nmr-and-ms
I use a similar program BioChemDraw that also have a 1H 13C simulator. But would be good if the diagram could be uploaded and then do a check.
Cl-C triple bond C-H
1-Chloro ethyne
That only have one chemical shift at about 2.5-3 if I had to guess
singlet
methane also u get singlet dude
CH3Cl
@Preetha @blues @aaronq
what happened dude
Nothing, just linked them to here. Non the less as far as I can see it we have the following situation: 3 protons see 2 protons < 3 protons see 3 protons < 2 protons see 1 proton < 2 protons see 3 protons. With this meaning we have 4 carbon atoms we know most contain hydrogen so: C: >=4 H: 10 O: ? maybe Cl
at first i would say there is a problem with pairing the signals. if 3 see 2 and 2 see 3 then it is clear. but if 2 see 1 you need to have 1 that sees 2...
Exactly...
then I would again question whether the signals at 2.x and 3.y are anything else but singlets badly assigned because of signal resolution.
man, i wish i could help you, but if you don't have a definite spectra, I'm afraid i can't.
Okay I found it: http://sdbs.riodb.aist.go.jp/sdbs/cgi-bin/direct_frame_disp.cgi?sdbsno=573 It was the right molecule what I guessed. When you look at the peak data (which I have been given) you can see all the ones I wrote. But what my beloved prof was so sweet to leave out was the intensity... When you look at the intensity for peak around 2 ppm we can see two relative quite different values in ppm which does not obey Pascal's triangle for intensity in NMR. I don't know if you out from that argument and observation can conclude it most be a singlet and the second value is caused by "long-distance-interference" or bag ground noise.
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