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Mathematics 19 Online
Parth (parthkohli):

Calculus question.

Parth (parthkohli):

Evaluating\[\lim_{h \to 0} \dfrac{f(1 + h) - f(1 - h)}{h}\]I used L'Hospital Rule.\[\lim_{h \to 0} {f'(1 + h) - f'(1 + h)} \quad \Rightarrow \quad f'(1) - f'(1) = 0\]But that is the wrong answer.

Parth (parthkohli):

\(f(x)\) is given, but I am not sure if we need it.

Parth (parthkohli):

Please don't laugh at me... I am just a beginner :-P

OpenStudy (anonymous):

I am not following entirely yet to be honest, but if you differentiate the second expression, shouldn't there be a plus sign? \[\Large f'(1+h)-f'(1-h)\cdot (-1) = f'(1+h)+f'(1-h) \]

Parth (parthkohli):

Oh!!!

Parth (parthkohli):

I can do the rest with what I am given as f(x). Thanks!

OpenStudy (anonymous):

so in that expression it would be: \[\Large f'(1)+f'(1)=2f'(1) \] seems elegant enough.

OpenStudy (anonymous):

you're welcome

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