What is the solution to the rational equation
+
=
@phi
you could practice using the equation editor
I would first factor the denominator of the very first fraction can you do that ?
First factor all denominators. Then multiply both sides by the LCD. This will eliminate all denominators.
hhaha how do i use the equation editor?
yes i can!!
click on the equation button below the input area in the lower left. you can play with it : learn by doing... meanwhile, can you factor the bottom of the first fraction ?
thanks and yes
what do you get ?
wait what am i looking for if it tells me what it equals
eventually, we will find x = something
you should get so far: \[ \frac{5}{(x-2)(x-1) }+ \frac{1}{x-2} = \frac{1}{3(x-1) } \]
One good strategy is multiply both sides by (x-2). that means all terms on both sides of the =. what do you get ?
huh??? what do i multiply that with?
do you see how we get \[ \frac{5}{(x-2)(x-1) }+ \frac{1}{x-2} = \frac{1}{3(x-1) } \]?
We start with \[ \frac{5}{x^2-3x+2 }+ \frac{1}{x-2} = \frac{1}{3x-3 } \] factor the bottom of the first fraction. that means re-write as(x-2)(x-1) factor out a 3 in the last fraction: 3(x-1) we get our new equation
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