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Mathematics 14 Online
OpenStudy (anonymous):

Hello, I can't understand how can you figure out what quadrant does the result of the following exercise belong to. Help welcomed. Thanks. Question 3: In a triangle ABC, we have that cos Y = 513, what is the values of sin Y? Solution: We have the basic trigonometric identity, Sin2 A + cos2 A = 1 In our case, we know cos Y = 513 sin2 Y = 1 - (513)2 sin2 Y = 1 - 25169 = 144169 sin Y = ± 144169‾‾‾‾√ = -1213. (Because cos Y is +ve, lies in lV quadrant. Value of sin Y is -ve in this quadrant.)

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