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Mathematics 12 Online
OpenStudy (anonymous):

A test for the level of potassium in the blood is not perfectly precise. Moreover, the actual level of potassium in a person's blood varies slightly from day to day. Suppose that repeated measurements for the same person on different days vary normally with .

OpenStudy (anonymous):

Standard deviation= 0.2.

OpenStudy (anonymous):

a) Julie's potassium level is measured once. The result is x-bar = 3.4. Give a 90% confidence interval for her mean potassium level. b) If three measurements were taken on different days and the mean result is x = 3.4, what is a 90% confidence interval for Julie's mean blood potassium level? c) How large a sample of Julie's potassium levels in the previous exercise would be needed to estimate her mean within 0.06 with 95% confidence?

OpenStudy (anonymous):

I ONLY NEED C @jim_thompson5910

OpenStudy (anonymous):

@amistre64 help with just C?

OpenStudy (anonymous):

My answers for a and b: (a) x bar = 3. n = 1 std = 0.2 z value = 1.645 3 plus/minus 1.645 (0.2/(sqrt1)) Interval = [3.07, 3.73] (b) x bar = 3. n = 3 std = 0.2 z value = 1.645 3 plus/minus 1.645 (0.2/(sqrt3)) Interval : [3.21, 3.59] (c)

OpenStudy (anonymous):

@jim_thompson5910 i only need c;)

jimthompson5910 (jim_thompson5910):

E = margin of error E = C*sigma/sqrt(n) 0.06 = 1.96*0.2/sqrt(n) solve for n

OpenStudy (anonymous):

oh ok

jimthompson5910 (jim_thompson5910):

tell me what you get

OpenStudy (anonymous):

0.06 = .392/sqrt(n)

jimthompson5910 (jim_thompson5910):

keep going

OpenStudy (anonymous):

sqrt n = 0.15306122449 ?

OpenStudy (anonymous):

0.15306122449 = sqrt(n) ?

jimthompson5910 (jim_thompson5910):

no something is off

OpenStudy (anonymous):

idk

jimthompson5910 (jim_thompson5910):

oh it should be 1/sqrt(n) = 0.15306122449

OpenStudy (anonymous):

ok then?

OpenStudy (anonymous):

im not asure what to do next

jimthompson5910 (jim_thompson5910):

solve for n

OpenStudy (anonymous):

sqrt(n) = 0.15306122449

jimthompson5910 (jim_thompson5910):

no it's 1/sqrt(n) = 0.15306122449

OpenStudy (anonymous):

.39123039821

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

you then multiply both sides by sqrt(n) to get 1 = 0.15306122449 *sqrt(n)

OpenStudy (anonymous):

ok

jimthompson5910 (jim_thompson5910):

keep going

OpenStudy (anonymous):

so its the sqrt of 0.15306122449

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

that times the square root of n

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

solve 1 = 0.15306122449 *sqrt(n) for n

OpenStudy (anonymous):

so divide sqrt n?

OpenStudy (anonymous):

1/sqrt n = 0.15306122449

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

but that gets you back where you started from

jimthompson5910 (jim_thompson5910):

so at this point you're going in circles

OpenStudy (anonymous):

ugh

OpenStudy (anonymous):

idk aht to do

jimthompson5910 (jim_thompson5910):

why not divide both sides by 0.15306122449 instead of sqrt(n)

OpenStudy (anonymous):

1 = 0.15306122449 *sqrt(n)

OpenStudy (anonymous):

6.53333333332 = sqrt n

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

last step?

OpenStudy (anonymous):

42.6844444443?

jimthompson5910 (jim_thompson5910):

now round to the nearest integer

OpenStudy (anonymous):

42.7

jimthompson5910 (jim_thompson5910):

because n = sample size (which is a whole number)

OpenStudy (anonymous):

43

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

you nailed it, that's the min sample size needed

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