A test for the level of potassium in the blood is not perfectly precise. Moreover, the actual level of potassium in a person's blood varies slightly from day to day. Suppose that repeated measurements for the same person on different days vary normally with .
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OpenStudy (anonymous):
Standard deviation= 0.2.
OpenStudy (anonymous):
a) Julie's potassium level is measured once. The result is x-bar = 3.4. Give a 90% confidence interval for her mean potassium level.
b) If three measurements were taken on different days and the mean result is x = 3.4, what is a 90% confidence interval for Julie's mean blood potassium level?
c) How large a sample of Julie's potassium levels in the previous exercise would be needed to estimate her mean within 0.06 with 95% confidence?
OpenStudy (anonymous):
I ONLY NEED C @jim_thompson5910
OpenStudy (anonymous):
@amistre64 help with just C?
OpenStudy (anonymous):
My answers for a and b:
(a)
x bar = 3.
n = 1
std = 0.2
z value = 1.645
3 plus/minus 1.645 (0.2/(sqrt1))
Interval = [3.07, 3.73]
(b)
x bar = 3.
n = 3
std = 0.2
z value = 1.645
3 plus/minus 1.645 (0.2/(sqrt3))
Interval : [3.21, 3.59]
(c)
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OpenStudy (anonymous):
@jim_thompson5910 i only need c;)
jimthompson5910 (jim_thompson5910):
E = margin of error
E = C*sigma/sqrt(n)
0.06 = 1.96*0.2/sqrt(n)
solve for n
OpenStudy (anonymous):
oh ok
jimthompson5910 (jim_thompson5910):
tell me what you get
OpenStudy (anonymous):
0.06 = .392/sqrt(n)
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jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (anonymous):
sqrt n = 0.15306122449 ?
OpenStudy (anonymous):
0.15306122449 = sqrt(n)
?
jimthompson5910 (jim_thompson5910):
no something is off
OpenStudy (anonymous):
idk
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jimthompson5910 (jim_thompson5910):
oh it should be 1/sqrt(n) = 0.15306122449
OpenStudy (anonymous):
ok then?
OpenStudy (anonymous):
im not asure what to do next
jimthompson5910 (jim_thompson5910):
solve for n
OpenStudy (anonymous):
sqrt(n) = 0.15306122449
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jimthompson5910 (jim_thompson5910):
no it's 1/sqrt(n) = 0.15306122449
OpenStudy (anonymous):
.39123039821
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
you then multiply both sides by sqrt(n) to get
1 = 0.15306122449 *sqrt(n)
OpenStudy (anonymous):
ok
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jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (anonymous):
so its the sqrt of 0.15306122449
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
that times the square root of n
OpenStudy (anonymous):
?
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jimthompson5910 (jim_thompson5910):
solve
1 = 0.15306122449 *sqrt(n)
for n
OpenStudy (anonymous):
so divide sqrt n?
OpenStudy (anonymous):
1/sqrt n = 0.15306122449
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
but that gets you back where you started from
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jimthompson5910 (jim_thompson5910):
so at this point you're going in circles
OpenStudy (anonymous):
ugh
OpenStudy (anonymous):
idk aht to do
jimthompson5910 (jim_thompson5910):
why not divide both sides by 0.15306122449 instead of sqrt(n)
OpenStudy (anonymous):
1 = 0.15306122449 *sqrt(n)
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OpenStudy (anonymous):
6.53333333332 = sqrt n
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
last step?
OpenStudy (anonymous):
42.6844444443?
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jimthompson5910 (jim_thompson5910):
now round to the nearest integer
OpenStudy (anonymous):
42.7
jimthompson5910 (jim_thompson5910):
because n = sample size (which is a whole number)
OpenStudy (anonymous):
43
OpenStudy (anonymous):
?
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