Mathematics
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OpenStudy (anonymous):
Can some one show me all the steps to evaluate the Integral of (tan^3xsec^3x) dx
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OpenStudy (anonymous):
\[\int\limits(\tan^3xsex^3x)dx \] Thats the problem I have to integrate...
hartnn (hartnn):
did you try u=sec x ?
hartnn (hartnn):
\(\int \tan x\sec x\sec^2x(\sec^2x-1)dx\)
hartnn (hartnn):
then put u=sec x
du ....?
OpenStudy (anonymous):
du= sec x tan x?
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hartnn (hartnn):
almost!
du =sec x tan x dx
OpenStudy (anonymous):
Haha lol yeah I always forget the dx :P
hartnn (hartnn):
\(\int u^2(u^2-1)du\)
pretty easier to integrate this.
OpenStudy (anonymous):
Okay and you replaced tan^2 with (sec^2x-1)?
hartnn (hartnn):
yes...
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hartnn (hartnn):
doubts ? any kind ?
OpenStudy (anonymous):
So its U^3/3(U^3/3-1)du?
OpenStudy (anonymous):
Then I just put back u, which is sec x
hartnn (hartnn):
what! no... :(
\(\int u^4-u^2 dx\)
hartnn (hartnn):
*du
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OpenStudy (anonymous):
Ohh oops XD I didnt know if you were supposed to do the algebra there or not :P
hartnn (hartnn):
now integrate
OpenStudy (anonymous):
Okay so now its u^5/5-u^3/3?
OpenStudy (anonymous):
Then replace u with sec x?
hartnn (hartnn):
now, yes!
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OpenStudy (anonymous):
So sec^5/5 - Sec^3/3
hartnn (hartnn):
+c
and correct.
OpenStudy (anonymous):
Thanks! :D
hartnn (hartnn):
welcome ^_^