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Calculus1 20 Online
OpenStudy (anonymous):

Rate problem:please plase help me. A spotlight on the ground shines on a wall 12m away. If a man 2m tall walks from the spotlight toward a building at a speed of 16ms, how fast is the length of his shadow on the building decreasing when he is 4m from the building?

OpenStudy (anonymous):

@satellite73 please help

OpenStudy (anonymous):

@calmat01

OpenStudy (anonymous):

ok, hang on.brb.

OpenStudy (anonymous):

ok,

OpenStudy (anonymous):

Ok, most important thing in Related rates problems is to draw a picture to get a sense of what is being asked. Have you drawn a picture?

OpenStudy (anonymous):

No i havnt. It confused me from the first step

OpenStudy (anonymous):

Sorry, my laptop is giving me issues...it keeps freezing. I will type it up and see if I can post it....give me a few as this thing is super slow!

OpenStudy (anonymous):

Haha its okay! thank you for taking your time

OpenStudy (anonymous):

I am almost done...give me a few more.

OpenStudy (anonymous):

its totally ok, thanks

OpenStudy (anonymous):

lol...I have it, you sure you don't want to see it?

OpenStudy (anonymous):

Heres's the picture.|dw:1363314443849:dw| By similar triangles \[\frac{ y }{ 12 }=\frac{ 2 }{ 12-x}\] Then just take the derivative of both sides WRT time.

OpenStudy (anonymous):

|dw:1363314756665:dw|Failed to mention y=length of shadow, and dx/dt=-16, we want dy/dt when x=4. @Dodo1

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