Austin wants to sketch the graph of a circle represented by the given equation.
(x + 6)2 + (y + 2)2 = 16
Using complete sentences, describe the steps used to sketch the circle on a coordinate grid
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OpenStudy (anonymous):
@jim_thompson5910 @Hero
OpenStudy (anonymous):
@ganeshie8
jimthompson5910 (jim_thompson5910):
can you identify the center?
OpenStudy (anonymous):
It would be (-6,-2)?
jimthompson5910 (jim_thompson5910):
good
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jimthompson5910 (jim_thompson5910):
the radius is____
OpenStudy (anonymous):
8 right?
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
in general, the radius of
(x-h)^2+(y-k)^2=r^2
is r
jimthompson5910 (jim_thompson5910):
so for example, the radius of
(x-2)^2+(y-9)^2=7^2
is r = 7
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OpenStudy (anonymous):
Alrighty
jimthompson5910 (jim_thompson5910):
so the radius of (x + 6)^2 + (y + 2)^2 = 16 is what?
OpenStudy (anonymous):
I wanna say -8 but i know thats wrong, so idk, im not good at this im sorry
jimthompson5910 (jim_thompson5910):
its ok, just don't give up
jimthompson5910 (jim_thompson5910):
16 is the same as 4^2, agreed?
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OpenStudy (anonymous):
oh yes, agree
jimthompson5910 (jim_thompson5910):
ok so that matches with the r^2
jimthompson5910 (jim_thompson5910):
so basically
r^2 = 16
r^2 =4^2
r = ???
OpenStudy (anonymous):
4?
jimthompson5910 (jim_thompson5910):
good
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jimthompson5910 (jim_thompson5910):
so to sum up what you found so far
center: (-6,-2)
radius: 4
jimthompson5910 (jim_thompson5910):
those two combined together uniquely determine a circle
jimthompson5910 (jim_thompson5910):
so basically that's all you need to draw the circle
jimthompson5910 (jim_thompson5910):
if you were doing it on paper, you would start with a blank xy axis like this
|dw:1363298825902:dw|
jimthompson5910 (jim_thompson5910):
you would then plot the center (-6,-2)
|dw:1363298850895:dw|