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what is the pH of a solution with a [H+]=3.74 x 10 ^-12 M?
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it would help to know what the formula for pH is. i believe it involves the common log
yeah, pH= -log[H+] but i have trouble plugging it into my calculator.... which seems to be my biggest issue...
Is that \(\log_{10}[H+]\)?
Is it base 10?
yes
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Because \[ \log_{10}(10^{-12}) = -12 \]
\[-\log(3.74\times 10^{-12})=-\log(3.74)+12\]
If you suppose something like \(\sqrt{10}\approx 3.74\) then \(\log_{10}(3.74)\approx 1/2\)
thx guys :)
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