Question

What is the 32nd term of the arithmetic sequence where a1 = -34 and a9 = -122?
-408
-397
-386
-375

Answer 1

What is the sum of a 52-term arithmetic sequence where the first term is 6 and the last term is 363?
8,487
8,856
9,225
9,594

What is the sum of a 22-term arithmetic sequence where the first term is 57 and the last term is -27?
240
270
300
330

What is the 9th term of the geometric sequence where a1 = -6 and a6 = -6,144?
-327,680
-393,216
-458,752
-524,288

What is the 7th term of the geometric sequence where a1 = 128 and a3 = 8?
0.03125
0.06
0.125
0.15625

What is the 6th term of the geometric sequence where a1 = -625 and a2 = 125?
-0.2
0.2
-0.04
0.04

Answer 2

The sum of a 52-term arithmetic sequence where
the first term is 6 and the last term is 363 is 9,594.

Sum of AP = {n(a + l)} / 2

Where, n = number of terms in Arithmetic progression

a = first term of Arithmetic progression

l = last term of Arithmetic progression

S52
= {n(a + l)} / 2
= {52(6 + 363)} / 2
= 26*369
= 9,594

Answer 3

3) The 9th term of the geometric sequence
where a1 = -7 and a6 = -7,168 is -458,752.

a1 = -7
a6 = -7 * r^5
-7,168 = r^5 * (-7)
r^5 = -7,168/-7 = 1024
r = 4

The n-th term of a geometric sequence
with initial value a and common ratio r is given by
an = ar^(n - 1)

a9 = -7*4^8 = -458,752

Answer 4

4) 0.03125

Answer 5

thank you:)