Question

Suppose that for a function f(x) we know that
f(3)=5 and f ' (3)=7
We also 'have that g(x)=x^2*f(x)
Find the equation of the line tangent to g(x) at x=3

Answer 1

can you give me g'(x) = ???

Answer 2

hello?

Answer 3

um wouln't it just be x

Answer 4

no... g(x) = x^2*f(x)
so use the product rule....

g'(x) = [x^2]'*f(x) + x^2*[f'(x)] = {simplify.....}

Answer 5

x^4*f(x)

Answer 6

how did u get that?

Answer 7

Wait sorry 2fx^3

Answer 8

Is this correct

Answer 9

no... use the product rule i showed above...

Answer 10

I am really confused I don't know how to do it any other way