Question

Please Help
solve for x: 4/x-3 + 5/x+3=6/x^2-9

Answer 1

(x^2-9 ) is the difference of two squares therefore it can also be expressed as (x-3) (x+3)
bring the left hand side of the equation under the same denominator

Answer 2

you should get 9x-3/(x-3)(x+3) = 6/ (x-3)(x+3)

Answer 3

this is the answer right

Answer 4

what i just posted no
x=1

Answer 5

so x=1 is the answer

Answer 6

yup

Answer 7

multiply all what by (x-3)(x+3)

Answer 8

what

Answer 9

ok but thats not the answer right

Answer 10

4 5 6
----- + ------- = --------
x -3 x +3 x^2 -9

first you need getting the common denominator so what is x^2 -9 what you can rewrite it like (x-3)(x+3) exactly how have wrote above @hammytams
so than now you need multiplie the numerator on the first fraction by (x+3) and the numerator on the second fraction by (x+3)

so in this way you will get

4(x+3) 5(x-3) 6
---------- + ---------- = ----------
(x-3)(x+3) (x-3)(x+3) (x-3)(x+3)

so than

4(x+3) + 5(x-3) = 6
4x+12 +5x -15 =6
9x -3 = 6
9x = 9

x= 9/9

x=1