Write an inequality to represent the problem. Then solve the inequality by writing the pairs which solve it.
Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18.

Question

Write an inequality to represent the problem. Then solve the inequality by writing the pairs which solve it.
Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18.

anonymous · Answer

10

anonymous · Answer

$0<n+n+2\leq 18$ might work

anonymous · Answer

it is easy enough to solve
smallest odd integer is 1, so 
1,3 works
3,5
5,7
etc

anonymous · Answer

well there are no too many more, might as well complete it

anonymous · Answer

Mmm it could, I just came up with 2n + 1 <= 18. Getting a second opinion coz a lot of the things I've tried have a lot of parings, don't want one with many :P

anonymous · Answer

they have to be positive, which is why i put the zero on the left

anonymous · Answer

also if they are consecutive ODD integers, then if one is $n$ the other is $n+2$

anonymous · Answer

7,9  is the last one, because $9+11=20$ is too large

anonymous · Answer

Ooohhh, okay! I get it now, thank you so much (: