Question

Find the coordinates of the image after a reflection in the given line.
[ 1 3 -2 1 9 5] y = -x

Answer 1

are your coordinates this (1;3) (-2;1) (9;5)?
if so then the general rule for reflecting about y=-x is A(x;y) --> A'(-y;-x)
so then (1;3) would become (-3;-1) & take note at this one (-2;1) becomes (-1;2) because you swap the x and y and then add a negative sign so you end up with -(-2) hence positive. and (9;5) becomes (-5;-9).

Answer 2

It's 1, 3 and -2 over 1, 9, and 5.

Answer 3

is that in 3 dimensions?

Answer 4

would it be: -1, -9, -5 over -1,-3, and 2?

Answer 5

it's a matrix with 2 rows and 3 columns

Answer 6

id tell you but then id have to kill u

Answer 7

Please, don't joke around.

Answer 8

lol

Answer 9

well do you get how to solve for 2 variables with 2 equations?

Answer 10

I got
-1 -9 -5
over
-1 -3 and 2
is that what any of you got?

Answer 11

you would have to multiply your matrix by the reflection matrix for y=-x which is \[\left[\begin{matrix}0 & -1 \\-1 & 0\end{matrix}\right] \]

Answer 12

check out this link http://people.bath.ac.uk/sej20/transform.html

Answer 13

How do I multiply a 2x3 matrix with a 2x2 matrix?

Answer 14

Oops! yes that doesnt make sense :(

Answer 15

I'm very confused :(