Use Stokes' Theorem to find the circulation of F=<2y, 5z, 5x> around the triangle obtained by tracing out the path (4,0,0) to (4,0,4), to (4,4,3) back to (4,0,0).
Can you define what circulation is?
i guess it's just going along the path from a point to another?
I guess they just want you to do: \[ \int_C \mathbf{F}\cdot d\mathbf{r} \]
i calculated the curl(F) first which was 5, and i multiplied that by 6 which was the region of the triangle but got the wrong answer
Well I'm guessing circulation is given by: \[ \iint_S \nabla \times \mathbf{F}\cdot d\mathbf{S} \]And by Stokes theorem: \[ \iint_S \nabla \times \mathbf{F}\cdot d\mathbf{S} = \int_C \mathbf{F}\cdot d\mathbf{r} \]
So basically, just do the line integral. Can you do it?
but what is the limit of the integral? from 0 to 4?
You have 3 curves.
(4,0,0) to (4,0,4) (4,0,4) to (4,4,3) (4,4,3) to (4,0,0)
Do the line integral across each one and add them up.
Do you know how to do a line integral?
Do you know how to parametrize the curves?
yes! :) i think i get it :P i'm solving it now :) thanks!!!
Wait... do you suppose it would be easier to find the surface and do the curl...?
yes but i got the wrong answer
What was your curl?
5
Curl is a vector dude....
curl doted with the normal vector is 5
that's the integrand
What was your curl and normal vector?
5,-5,-2 and 1.0.0
Also, your surface parametrization was?
oh i got the right answer! thanks a lot!
Yeah but I feel like we cheated.
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