Question

PROVE:

Answer 1

\[\frac{ 1+\sin \theta }{ 1-\sin \theta }-\frac{ 1-\sin \theta }{ 1+\sin \theta }=4\tan \theta*\sec \theta\]

Answer 2

what have u tried ?

Answer 3

I am stuck at some place

Answer 4

which step ?

Answer 5

-2cos^2theta/cos^2theta

Answer 6

denominator, obviously is cos^2 theta
lets see numerator from beginning,
(1+s)^2-(1-s)^2
{s= sin theta}
can you simplify this ?

Answer 7

1+s/1-s - 1-s/1+s

Answer 8

not 1+s^2
its (1+s)(1+s) = (1+s)^2

Answer 9

(1+s)^2-(1-s)^2/(1-s)(1+s)

Answer 10

yes, go ahead