Question

where is everyone?!? help please! =(
find the extrema: 4x^3-13x^2+4x+1
max and min:
[1,4]
[0,2]

Answer 1

i put the answer: [1,4] max=65 min= -11 and for [0,2] max= 196 min= -11

what's wrong with the answer?

Answer 2

i found the derivative..12x^2-26x+4

Answer 3

then i factored: and got the critical points: x=1/6 and x=2

Answer 4

then i evaluated f at each critical number

Answer 5

and then evaluated f at each endpoints

Answer 6

left point: critical points: Right point:
f(1) -4 f(1/6)= 1.32407 f(4)= 65
f(0)=1 f(2)= -11 f(5)= 196

Answer 7

now can anyone tell me what i did wrong with the answer?
[1,4] max=65 min= -11
[0,2] max= 196 min= -11

Answer 8

@hartnn :(

Answer 9

@dan815

Answer 10

@wio

Answer 11

iam here

Answer 12

why you took f(5) ?

Answer 13

range is [0,2] right ?

Answer 14

sorry everyone.... hehe

Answer 15

so for for [0,2] max= 1min= -11

Answer 16

i see nothing else wrong besides f(5)