Question

How to solve:
18v divided by 3v^2
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t^2 - 4t + 3 6t - 6

Answer 1

\[\frac{ 18v }{ t^2 - 4t + 3 } \div \frac{ 3v ^2 }{ 6t - 6 }\]

Answer 2

lets start
step 1: factorize t^2 -4t +3 ans tell me what you get

Answer 3

(t - 3) (t - 1)

Answer 4

great...
and you know
(a/b) / (c/d) = (a/b) * (d/c)

so can you cancel the common factors now and get to the answer?

Answer 5

But there are no common factors out of
\[\frac{ 18v }{ (t-3)(t - 1) } \times \frac{ 6t - 6 }{ 3v^2 }\]

Answer 6

i can see that v can cancel out from 18v and 3v^2
and (t-1) also because 6t-6 is 6*(t-1)

Answer 7

\[\frac{ 18v }{ (t-3)(t-1) }\div \frac{ 3v^2 }{ 6(t-1) }\]\[\frac{ 18v }{ (t-3)(t-1) }\times \frac{ 6(t-1) }{ 3v^2 }\]Cancels (t-1), 18 becomes 6 and 3 becomes 1, v cancels in the numerator and v2 becomes v\[\frac{ 6 }{ t-3}\times \frac{ 6 }{ v }\]\[\frac{ 36 }{ v(t-3) }\]\[\frac{ 36 }{ tv-3v }\]

Answer 8

@haileemackk
i wanted you to figure out the steps but Lynncake did all the steps
so clear now?

Answer 9

i think i understand now. thank you for your help