Which number makes this equation true?
v^2 + 10v + 16 = (v + 8)(v + ?)
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OpenStudy (anonymous):
@jim_thompson5910
Parth (parthkohli):
I know a shortcut... can I say it?
jimthompson5910 (jim_thompson5910):
if you were to set up a table, the lower right corner would have the value of 8*? where the answer would replace the question mark
OpenStudy (anonymous):
yes please @ParthKohli
jimthompson5910 (jim_thompson5910):
8*? has to equal 16
so basically
8p = 16
p = ???
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jimthompson5910 (jim_thompson5910):
where p is that answer
OpenStudy (anonymous):
2
jimthompson5910 (jim_thompson5910):
yep, you nailed it
OpenStudy (anonymous):
yayyy :)
jimthompson5910 (jim_thompson5910):
so
v^2 + 10v + 16 = (v + 8)(v + ?)
turns into
v^2 + 10v + 16 = (v + 8)(v + 2)
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OpenStudy (anonymous):
What is the factored form of x^2 + 6x + 8?
Parth (parthkohli):
The shortcut says that in \(v^2 + \color{blue}{10}v + \rm something \) and \((v + \color{green}{a})(v + \color{green}{b})\), the sum of the greens is the blue guy.
jimthompson5910 (jim_thompson5910):
find two numbers that
a) multiply to 8 (last term)
AND
b) add to 6 (middle coefficient)
OpenStudy (anonymous):
im confused @ParthKohli
OpenStudy (anonymous):
2 and 4 . @jim_thompson5910
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Parth (parthkohli):
It's simple.
You have \((v + 8)(v + ?)\). This shortcut says that \(8 + ? = 10\).
jimthompson5910 (jim_thompson5910):
So x^2 + 6x + 8 factors to (x+2)(x+4)
The rule is that x^2 + bx + c factors to (x+m)(x+n) where m+n = b and m*n = c
OpenStudy (anonymous):
ohhh! @ParthKohli thanks :)
jimthompson5910 (jim_thompson5910):
So it's just a matter of finding those two numbers then writing it in the form (x+number1)(x+number2)
Parth (parthkohli):
I know that was sarcastic. -_-
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OpenStudy (anonymous):
hold on im thinking @jim_thompson5910
OpenStudy (anonymous):
5 and 3?? @jim_thompson5910
jimthompson5910 (jim_thompson5910):
you found the numbers already by saying 2 and 4
2+4 = 6 (middle coefficient)
2*4 = 8 (last term)
OpenStudy (anonymous):
ohh.
jimthompson5910 (jim_thompson5910):
so because you found two numbers that multiply to 8 AND add to 6
the factorization of x^2 + 6x + 8 would be (x+2)(x+4)
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OpenStudy (anonymous):
so it's (x + 4)(x + 2) ?
jimthompson5910 (jim_thompson5910):
go ahead and expand out (x+2)(x+4)
you'll find that you'll get x^2 + 6x + 8 back again
jimthompson5910 (jim_thompson5910):
so essentially what you've done is gone in reverse of expanding (which was done in the previous problem)
OpenStudy (anonymous):
i mostly get what you're saying. i have one more if you're willing to help?
jimthompson5910 (jim_thompson5910):
correct, the order of the factors doesn't matter
so (x+2)(x+4) is the same as (x+2)(x+4)
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jimthompson5910 (jim_thompson5910):
i meant (x+2)(x+4) is the same as (x+4)(x+2)
jimthompson5910 (jim_thompson5910):
sure go for it
OpenStudy (anonymous):
What is the factored form of x^2 – 7x + 12?
and dont worry i knew what you meant lol
jimthompson5910 (jim_thompson5910):
same idea, just different numbers
jimthompson5910 (jim_thompson5910):
find two numbers that multiply to 12 AND add to -7
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OpenStudy (anonymous):
-3 and -4
jimthompson5910 (jim_thompson5910):
perfect
jimthompson5910 (jim_thompson5910):
so it factors to (x-3)(x-4)
OpenStudy (anonymous):
(x – 4)(x – 3) ?
jimthompson5910 (jim_thompson5910):
unfortunately this trick only works if the leading coefficient is 1, but it's still useful
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jimthompson5910 (jim_thompson5910):
you got it
jimthompson5910 (jim_thompson5910):
that's the same as (x-3)(x-4) because the order of the factors does not matter
ex: 2 time 3 = 6 and 3 times 2 = 6
OpenStudy (anonymous):
okay i have a different kind of problem...
The area of a garden is given by the trinomial g2 – 2g – 24. The garden’s length is g + 4. What is the garden’s width?
jimthompson5910 (jim_thompson5910):
well it's actually the same type of problem, just worded differently
jimthompson5910 (jim_thompson5910):
they want you to factor g^2 - 2g - 24
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jimthompson5910 (jim_thompson5910):
what do you get when you do?
OpenStudy (anonymous):
write me an equation then and let me solve it :)
OpenStudy (anonymous):
like for the question
jimthompson5910 (jim_thompson5910):
find me two numbers that multiply to -24 and add to -2 at the same time
OpenStudy (anonymous):
-6 and -4
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jimthompson5910 (jim_thompson5910):
-6 plus -4 = -10 and it does NOT equal -2
jimthompson5910 (jim_thompson5910):
so try again
OpenStudy (anonymous):
oops lol hold on
OpenStudy (anonymous):
-6 and 4?
-6*4= 24
-6+4 = -2
i think lol
jimthompson5910 (jim_thompson5910):
good
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jimthompson5910 (jim_thompson5910):
So g^2 - 2g - 24 factors to (g-6)(g+4)
jimthompson5910 (jim_thompson5910):
notice how g+4 is a factor
jimthompson5910 (jim_thompson5910):
the other factor is g-6
jimthompson5910 (jim_thompson5910):
let's go back to the question
The area of a garden is given by the trinomial g2 – 2g – 24. The garden’s length is g + 4. What is the garden’s width?
OpenStudy (anonymous):
g-6!
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jimthompson5910 (jim_thompson5910):
correct since Area = Length times Width
OpenStudy (anonymous):
:D
jimthompson5910 (jim_thompson5910):
so if you have some area expression and you factor it, you get (Length)*(Width) where length and width are the factors of the area
OpenStudy (anonymous):
I actually get that!
jimthompson5910 (jim_thompson5910):
it only works for rectangles though
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jimthompson5910 (jim_thompson5910):
that's great
OpenStudy (anonymous):
hb this one?
What is the factored form of 4x^2 + 12x + 5?
jimthompson5910 (jim_thompson5910):
ok now the leading coefficient isn't 1 anymore, so we can't use that trick (well not the whole thing anyways)
jimthompson5910 (jim_thompson5910):
but we can still use some of the trick
jimthompson5910 (jim_thompson5910):
first multiply 4 (first coefficient) and 5 (last term) to get 4*5 = 20
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jimthompson5910 (jim_thompson5910):
now list two numbers that multiply to 20 AND add to 12 (middle coefficient)
OpenStudy (anonymous):
2 and 10
OpenStudy (anonymous):
is it (4x + 5)(x + 1) ?
jimthompson5910 (jim_thompson5910):
so we break 12x into 2x + 10x
then we factor by grouping
4x^2+12x+5
4x^2+2x+10x+5
(4x^2+2x)+(10x+5)
2x(2x+1)+(10x+5)
2x(2x+1)+5(2x+1)
(2x+5)(2x+1)
jimthompson5910 (jim_thompson5910):
hopefully factoring by grouping is a familiar term
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OpenStudy (anonymous):
so the final answer is (2x + 1)(2x + 5), right?
jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
hopefully you see how I got all that
OpenStudy (anonymous):
okay, thanks :D and lol yeah mostly.
OpenStudy (anonymous):
The area of a rectangular swimming pool is 10x2 – 19x – 15. The length of the pool is 5x + 3. What is the width of the pool?
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jimthompson5910 (jim_thompson5910):
alright, just keep practicing and it'll make more sense
jimthompson5910 (jim_thompson5910):
10*(-15) = -150
jimthompson5910 (jim_thompson5910):
find two numbers that multiply to -150
and
they add to -19
OpenStudy (anonymous):
why do you multiply 10 and -15?
jimthompson5910 (jim_thompson5910):
because I'm using the AC method for factoring
this method starts out by multiplying the first and last coefficients
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jimthompson5910 (jim_thompson5910):
then you find two numbers that multiply to that result and add to the middle number
OpenStudy (anonymous):
so the formula is ax^2 + bx + c right?
jimthompson5910 (jim_thompson5910):
that's a basic form of a quadratic, yes
jimthompson5910 (jim_thompson5910):
you would multiply 'a' and 'c' to get a*c or just ac
then you find two numbers that multiply to ac and add to b
jimthompson5910 (jim_thompson5910):
so that's why they call it the ac method
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OpenStudy (anonymous):
I cant find the two numbers that multiply to -150 and add to -19..
OpenStudy (anonymous):
im too dumb..
jimthompson5910 (jim_thompson5910):
no you're not
jimthompson5910 (jim_thompson5910):
stop that
jimthompson5910 (jim_thompson5910):
there's a long list to check, but luckily there's a shortcut
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jimthompson5910 (jim_thompson5910):
have you heard of the quadratic formula before?
OpenStudy (anonymous):
noo. my teacher sucks this year. she is retiring so she doesnt teach us anything useful, she just assigns stuff and tells us to read our book to figure out how to do it, but the book has no tips or tricks.