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Mathematics 15 Online
OpenStudy (luigi0210):

solve the integral

OpenStudy (luigi0210):

\[\int\limits_{0}^{4}(1-\sqrt{u})/(\sqrt{u})\]

OpenStudy (anonymous):

Lolz...didn't even neded to substitute.

OpenStudy (anonymous):

need*

OpenStudy (anonymous):

waste of your time.

zepdrix (zepdrix):

Yah the substitution was kinda silly :) If you do a substitution, don't forget to change the limits of integration also.

OpenStudy (anonymous):

And there's no du at the back of the integral

OpenStudy (anonymous):

So there's no solution

OpenStudy (anonymous):

You can't continue on integrating that without respect of anything.

OpenStudy (luigi0210):

Ops, sorry forgot about the du.. It is in respect to du

OpenStudy (anonymous):

What are you integrating with respect to? You integrating with respect to zero?

OpenStudy (anonymous):

Okay. Now you can integrate it. Just separate the numerator.

OpenStudy (anonymous):

And you can continue integrating per usual.

OpenStudy (anonymous):

\[\int\limits_{}^{}\frac{ 1 }{ \sqrt{u} }du-\int\limits_{}^{}1du\]\[\int\limits_{}^{}u^{-\frac{ 1 }{ 2 }}du-u\]\[2u^{\frac{ 1 }{ 2 }}-u\]Then just plug in the limit from 0 to 4

OpenStudy (luigi0210):

My only real problem is finding the anti-derivative

OpenStudy (anonymous):

Anti-differentiating is just differentiating in reverse. Try and use reverse psychology when integrating if you can.

zepdrix (zepdrix):

\[\large \frac{1-\sqrt u}{\sqrt u} \qquad = \qquad \frac{1}{\sqrt u}-\frac{\sqrt u}{\sqrt u} \qquad = \qquad u^{-1/2}-1\] Yah you just apply the `Power Rule for Integration`! :D

OpenStudy (luigi0210):

Thank you very much

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