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Mathematics 7 Online
OpenStudy (anonymous):

help with problem 45!

OpenStudy (anonymous):

Directrix (directrix):

@jenny508 Is this the problem: x ≤ 2 and x≥-3 and x<(5/2) and x≥-5

Directrix (directrix):

Look and the graphs and determine which interval is all of these colors: green, gold, blue, and pink.

OpenStudy (anonymous):

Ok

Directrix (directrix):

So, what did you get? Post that and I'll tell you what I got.

OpenStudy (anonymous):

I don't get it

Directrix (directrix):

Look from left to right on the graphs. Which is the first point that is contained in all the graphs?

Directrix (directrix):

What is the x that goes with that pink dot? (on the left of the graph)

Directrix (directrix):

Talk to me. Where does the black segment I drew touch the number line?

Directrix (directrix):

Alrighty, then. I have to go. I'll save the second part for the endpoint of the common interval to use in case I see you online again.

OpenStudy (anonymous):

X> -3

OpenStudy (anonymous):

Okay later

Directrix (directrix):

Well, you have a candidate for the left endpoint. Let me see what I got.

Directrix (directrix):

-3, yes. -3 is is on all those graphs. So, the common interval will begin - 3 ≤ x ?

OpenStudy (anonymous):

I think so

Directrix (directrix):

Now, look at the same set of graphs on the attachment below. Where does the vertical black segment cut the number line. That is the biggest point on all four of the given inequalities.

Directrix (directrix):

And, the right endpoint is ? @jenny508

OpenStudy (anonymous):

X<5/2

Directrix (directrix):

Too large. The number coordinate that goes with the blue dot. Check out this diagram.

Directrix (directrix):

The blue dot is directly above the number what ?

OpenStudy (anonymous):

2 1/2

Directrix (directrix):

Too big. Drop back to an integer.

Directrix (directrix):

Directrix (directrix):

Look again. I pulled out the blue graph for easier viewing.

Directrix (directrix):

Here is where we are --> - 3 ≤ x ≤ If you give that number with the blue dot over it, it goes at the end of the inequality statement above.

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