A golf ball m=0.14 kg is dropped from height h. It interact with th floor for t=0.13s and it applis a force of F =13N to the floor when it elastically collides with it.
Write an expression for the ball's velocity, v, just after it reboud from the floor in terms of F, t, and m.

Question

A golf ball m=0.14 kg is dropped from height h. It interact with th floor for t=0.13s and it applis a force of F =13N to the floor when it elastically collides with it.
Write an expression for the ball's velocity, v, just after it reboud from the floor in terms of F, t, and m.

anonymous · Answer

im confuse can you please assist me? anyone?

.sam. · Answer

Initial momentum, $$p_i=m(-v_i)$$
Final momentum,  $$p_f=mv_f$$
Force on ball, $$F=\frac{\Delta p}{\Delta t}=\frac{p_f-p_i}{t} \ \ F=\frac{mv_f+mv_i}{t} \ \ \frac{Ft}{m}=v_f+v_i$$
When elastic collisions, $$v_f=v_i$$
$$\frac{Ft}{m}=2v \ \ v=\frac{Ft}{2m}$$

anonymous · Answer

thanks so much