Explain why (–4x)0 = 1, but –4x0 = –4.
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(–4x)^0 = 1, but –4x^0 = –4.
Do you mean to say \((-4x)^0 =-1\)?
anything raised to the power of zero is 1
so (-4x)^0 = 1 and you have (-4)(x^0) = (-4)(1) = -4
Your PEMDAS says that you must first raise \(x\) to the power zero.\[-4 x ^0\]\[= -4 \times 1\]\[= -4\]
But PEMDAS also says that you have to consider the parentheses first.\[(-4x)^0\]\[= (-4)^0 \times x^0\]\[=1 \times 1\]\[= 1\]
the parenthesis is basically telling u that u are taking the whole equation -4x and raising it to the 0 power which makes it 1. for the -4x0 u are actually raising the x to the 0 power making it 1 then u multiply the -4 to the 1 making it -4 :) u just have to pay attention to the parenthesis.
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