Question

Find the sum to n series..
1*2*3+2*3*4+3*4*5....

Answer 1

You mean like \(1! + 2! + 3! \cdots n!\)?

Answer 2

\[\LARGE n(n+1)(n+2)(n+3)(n+4)(n+5)(n+6)(n+7)(n+8)(n+9(\]

Answer 3

720 so far

Answer 4

oh never mind

Answer 5

:-O
Don't intimidate me

Answer 6

You re now intimidated.

Answer 7

omg my DP is looking so cool cant believe :P

Answer 8

well than

Answer 9

Hmm, the product of an arithmetic sequence. http://en.wikipedia.org/wiki/Arithmetic_progression#Product

Answer 10

I don't get any of it. Do you just want it from \(n\) till \(n + 9\)?

Answer 11

lol

Answer 12

:O

If \(n \le 0 \) then \(0\). Otherwise, it diverges.

Answer 13

nahi aata to try mat kar:P

Answer 14

Arrey, sach mein!

Answer 15

I know a/1-r not talking bout that

Answer 16

Arrey, mujhe bhi pata hai =_=

Answer 17

You are looking for \(n(n + 1)(n + 2)(n + 3)\cdots (n + \infty)\)

Answer 18

:)

Answer 19

\[= \begin{cases} 0 : n \le 0 \\ \infty : n > 0 \end{cases}\]

Answer 20

OK? :-)

Answer 21

yes

Answer 22

:-)

Answer 23

answer is
n(n+1)(n+2)(n+3)(n+4)/4 -_-

Answer 24

@yrelhan4 ye bataega ab!!

Answer 25

What? The answer to \(n(n + 1)(n + 2)(n + 3)\cdots(n + \infty)\)? =_=

Answer 26

dude rehne de :P

Answer 27

@RnR

Answer 28

sorry, wrong browser lol

Answer 29

hmm. sochne de..

Answer 30

ncert..1st ques~~~~~:P

Answer 31

\[1(1 + 1)(1 +2)(1 + 3)(1 + 4)\cdots = \dfrac{1(1 + 1)(1 + 2)(1 + 3)}{3}\]? -_-

Answer 32

Oh wait...

Answer 33

dude rehne de

Answer 34

kisi ne wish you were here suna hai?

Answer 35

samaj gaya?:P no

Answer 36

:')

Answer 37

What do you mean by "what is the sum to n series"? =_=

Answer 38

ek baar question check kar... galat lag rha hai..

Answer 39

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

Answer 40

FIXED :P

Answer 41

http://in.answers.yahoo.com/question/index?qid=20110420091611AAY6Q4F this is the question. :/

Answer 42

Ah.\[1(1 + 1)(1 + 2) + 2(2 + 1)(2 + 2) + 3(3 +1)(3 + 2)\cdots n(n + 1)(n + 2)\]

Answer 43

bbye. (y)
aur mereko maths vale question me aage se sirf tag krna. answer mat puchna. :/

Answer 44

arre?

Answer 45

\[n(n + 1)(n + 2) = n(n^2 + 3n + 2) = n^3 + 3n^2 + 2n\]

Answer 46

\[\sum_{n = 1}^{k} k^3 + 3k^2 + 2k\]

Answer 47

k^3 ka expansion kaise kiya

Answer 48

mai sachi bataun...... mereko 1*2*3*3*5*6 lagaa tha. :o

Answer 49

Arrey, yeh main time waste kar raha hoon

@RnR ki link dekho @DLs

Answer 50

dang..

Answer 51

lol..niceone @RnR :P

Answer 52

how do i expand K^3

Answer 53

K^3 ka summation kya hota hai?

Answer 54

\[\left(1^3 + 2^3 + 3^3 \cdots n^3\right) = \left(1^2 + 2^2 + 3^2 \cdots n^2\right)^2\]

Answer 55

wahi?to/?

Answer 56

arre sahi bata rha hun. nhi manna na mano..

Answer 57

So\[\sum_{k = 1}^{n} k^3 =\left(\dfrac{k(k + 1)}{2}\right)^2\]

Answer 58

how

Answer 59

wahi main question hai :/

Answer 60

Oops.\[\left(\dfrac{k(k + 1)(2k + 1)}{6}\right)^2 \]

Answer 61

Ek aur formula se confuse ho gaya -_-

Answer 62

Induction se prove karo

Answer 63

http://www.flipkart.com/home-kitchen/kitchen-appliances/induction-cooktops/pr?sid=j9e%2Cm38%2C575 Yahan pe dekh lo

Answer 64

Prestige ke theek-theek hai induction chulhe