Do whaaat?!?!?!

Can someone help me out please?

Graph f(x)= 2log3(x)
Plot at least 2 points on the graph, draw all asymptotes.

Question

Do whaaat?!?!?! 

Can someone help me out please?


Graph f(x)= 2log3(x)
Plot at least 2 points on the graph, draw all asymptotes.

amistre64 · Answer

log 1 = 0  should be simple to do

anonymous · Answer

$$f(x)=2\log _{3}x$$

amistre64 · Answer

logb(b) = 1  is another property

amistre64 · Answer

and log 0 is undefined ...

anonymous · Answer

Can you walk me through it? I'm completely lost.

amistre64 · Answer

i just reiterated 3 properties of logs that will be useful to you

stamp · Answer

$$log_ax=y\ \rightarrow a^y=x$$

amistre64 · Answer

when x=1, y=0

when x=3, y=2

when x=0 we are undefined and have an asymptote ....

anonymous · Answer

ahhh ok

stamp · Answer

see the attachment for a graph

amistre64 · Answer

that looks very graphic yes :)

stamp · Answer

notice$$f(1)=0\rightarrow(1,0)$$ like amistre64 said

stamp · Answer

and (3, 2) is another noticeable point on the graph.

also, you cannot evaluate a negative log value.

that is why x > 0

anonymous · Answer

So my asymptotes would be 0,1,2,3 ?

stamp · Answer

No.

You need to understand what an asymptote is.

amistre64 · Answer

think of an asymptote as something unreachable, but that can be snuggled up to.

stamp · Answer

x = 0 is an asymptote, you can approach it but you can never attain it because at x = 0, the function does not exist / is undefined.

Look at the graph, notice how the graph shows f(x) approaching - infinity. The closer it gets to - infinity, the more vertical the slope of the function becomes, it approaches a vertical line. 

x = 0 is an asymptote

stamp · Answer

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