Question

By using the method [acosθ+bsinθ=ccos(θ+α)] Find values of θ up to 360 degrees from equation 2sinθ+4cosθ=√5

Answer 1

Let 2sin/theta/ +4 cos/theta/ = rcos(theta + alpha) then
2sin/theta/ + 4cos/theta/ = r(costheta * cosalpha - sintheta * sinalpha)
2 sin/theta/ + 4cos/theta/ = (-r*sinalpha)sin/theta/ + (r cosalpha) cos/theta/
=>-rsinalpha =2
=>r cosalpha =4

Answer 2

Now, can u find r and alpha?

Answer 3

Yes should be ok from here. Thats great thanks

Answer 4

welcome

Answer 5

Just gone through it again fully got it now thanks again. Very quick math from you

Answer 6

welcome again