2 particles of mass 30g and 40g respectively both travel at a speed of 35m/s in directions at right angles. The 2 particles collide and stick together. Calculate their speed after impact.

Question

anonymous · Answer

This is moentum promblem
$$m_1v_{1i}+m_2v_{2i}=(m_1+m_2)v_f\
30(35\hat{i})+40(35\hat{j})=(30+40)v_f\
v_f=35\hat{i}+35\hat{j} 
$$

anonymous · Answer

I assumes m1 travelling along +ve X-axis and m2 along +ve y-axis
resultant travels at a speed of $$35\sqrt{2}$$m/s 45° North of +ve X-axis

anonymous · Answer

I solved it the same way but the answer sheet say it's 25m/s. O_o

anonymous · Answer

what they got is $$35/\sqrt{2}$$

anonymous · Answer

Thank you.

anonymous · Answer

but wonder how!!!