A polynomial expression is shown below: (10x^5 + 5x^3 + x) - (x + 21)(2nx^2 + 1) The expression is simplified to: 10x^5 - 19x^3 - 504x^2 - 21 What was the value of n?
where is your n in the simplified equation? or did you just set it to =n
lol there is no = sign,you are missing some part
The first equation is \[(10x ^{5}+5x ^{3}+x)-(x+21)(2nx ^{2}+1)\] The n is in the term "2nx^2"
That's all the info they gave me for the question.
im asking about 10x^5 - 19x^3 - 504x^2 - 21 where is the n
It was simplified using n's value... which I don't know.. they want me to find out what n's value was.
ohhhhhhh i remember these... let me do research, this was a long time ago for me
Alrighty
well looking at the 5x^3 turning into -19x^3 we know that the (2n)+5 needs to be -19
19+5 is 24 so the term needs to be -24x^3 sooooo n=12
and its a positive 12 because the negative is going to be distributed
(2nx^2 + 1) is (12x^2+1)
sorry ((2(12))x^2+1)
@TammisaurusRex still confused?
not sure, if she is or not. @calmat01
Well, was just curious because she may still be looking it over, but everything you did is perfect...n=12 is correct.
@calmat01 thank you for checking! yeah, she hasnt responded so im not sure.
No problem.
Thank you! (: You're right, yes
no worries
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