Question

Find the Laplace Transform of the following below:

......(entering)

Answer 1

Laplace transform of the following \[\int\limits_{0}^{x} \sin 2t dt\]

Answer 2

There is a property that states the laplace transform of the integral from 0 to x of f(t) is equal to (1/s)F(s).

if i evaluate that integral first, and then take the laplace transform of that i will get
F(s)= s/(2s^2+4) + 1/2s

but if I wanted to check what I got with the property (1/s)F(s), what would be my original F(s)?

I guess I am really not sure if i did this problem right or not

Answer 3

@experimentX

Answer 4

the original F(s) = laplace transform of your function .. that is sin(2t)

Answer 5

okay, well the laplace transform of that is 2/(s^2 + 4)

and if I multiply that by (1/s), what i got above, so where did i go wrong?

Answer 6

Hold on a sec ... i need to check.
http://www.wolframalpha.com/input/?i=LaplaceTransform%5BIntegrate%5BCos%5Bb+x%5D%2C%7Bx%2C+0%2C+t%7D%5D%2C+t+%2C+s%5D

Answer 7

why did you use cos instead of sin?

Answer 8

doesn't matter ... anyway the condition seems to be valid. Let's see how can we get done with it.