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Find the 6th term of the sequence in which t1 = -5 and tn = -5tn-1.
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You have \[t _{n}=-5t _{n-1}\] correct?
yea
ok, so each succeeding value is just -5 times the previous value.
so \[t _{6}=t _{0}\left( -5 \right)^{6-1}\] and t_0=1
so that would be -25
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ummm...t_2=25, but t_6 is way more than that.
(-5)x(-5)x(-5)x(-5)x(-5)=-3125
ok thank you!!! :)
YW!
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