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OpenStudy (anonymous):
Find the sum of the geometric series by using a formula?
1-4+16-64+256-1024+4096?
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OpenStudy (tkhunny):
Rewrite: \(1 + 1\cdot (-4) + 1\cdot(-4)^{2} + 1\cdot(-4)^{3} + 1\cdot(-4)^{4} + 1\cdot(-4)^{5} + 1\cdot(-4)^{6}\)
OpenStudy (anonymous):
Do you know the formula for the sum of a finite geometric series?
OpenStudy (anonymous):
Yes it's
Sn=a1 { (1+1)^n -1/1
OpenStudy (anonymous):
hmmm...may want to try that again, it looks a little off, unless I am misreading it.
OpenStudy (tkhunny):
I do, but I never use it. I just make it up on the fly. Let's see...\(\dfrac{1 - 1\cdot(-4)^{7}}{1-(-4)}\)
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OpenStudy (anonymous):
\[Sn=a _{1} \left[ (1+1)^{n}-1 \right] / 1\]
OpenStudy (anonymous):
\[S _{n} = a _{1}\frac{ 1-r ^{n} }{ 1-r } \]
OpenStudy (anonymous):
Yes, yes, yes. sorry
OpenStudy (anonymous):
a1=1, n=7 and that's all we need.
OpenStudy (anonymous):
\[S _{7}=\frac{ 1-\left( -4 \right)7 }{ 1-(-4) }\] which becomes \[\frac{ 16385 }{ 5 }=3277\]
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OpenStudy (anonymous):
ok, I see
OpenStudy (anonymous):
Good, coz all I see are commands...stupid pc is not enabling math...lol
OpenStudy (tkhunny):
Just learn where the formula comes from. FAR more useful than memorizing a formula!
OpenStudy (anonymous):
Agreed @tkhunny
OpenStudy (anonymous):
Thanks a lot guys!
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