Find the sum of the geometric series by using a formula? 1-4+16-64+256-1024+4096?
Rewrite: \(1 + 1\cdot (-4) + 1\cdot(-4)^{2} + 1\cdot(-4)^{3} + 1\cdot(-4)^{4} + 1\cdot(-4)^{5} + 1\cdot(-4)^{6}\)
Do you know the formula for the sum of a finite geometric series?
Yes it's Sn=a1 { (1+1)^n -1/1
hmmm...may want to try that again, it looks a little off, unless I am misreading it.
I do, but I never use it. I just make it up on the fly. Let's see...\(\dfrac{1 - 1\cdot(-4)^{7}}{1-(-4)}\)
\[Sn=a _{1} \left[ (1+1)^{n}-1 \right] / 1\]
\[S _{n} = a _{1}\frac{ 1-r ^{n} }{ 1-r } \]
Yes, yes, yes. sorry
a1=1, n=7 and that's all we need.
\[S _{7}=\frac{ 1-\left( -4 \right)7 }{ 1-(-4) }\] which becomes \[\frac{ 16385 }{ 5 }=3277\]
ok, I see
Good, coz all I see are commands...stupid pc is not enabling math...lol
Just learn where the formula comes from. FAR more useful than memorizing a formula!
Agreed @tkhunny
Thanks a lot guys!
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