Protons are accelerated by electromagnets around a circular chamber with a radius of 1 km to speeds near the speed of light before colliding with a target to produce large amounts of energy. If a proton is traveling at 10% the speed of light, how much centripetal force is exerted by the electromagnets? (speed of light is 3 X 10^8 m/s and the mass of a proton is 1.67 X 10^-27 kg)

Question

abb0t · Answer

Use: 
$$F_c = \frac{ mv^2 }{ r }$$
m= mass of one proton 
v= 10% of speed of light 
r= radius (IN METERS)

anonymous · Answer

I know to use that formula but I am having trouble putting the numbers into it. The mass is 1.67*10^-27

abb0t · Answer

You already have the given information. Just plug it in.

abb0t · Answer

You might want to convert 1 km -> metres.

anonymous · Answer

Which would be .001m?

abb0t · Answer

no.

abb0t · Answer

1000 metres

anonymous · Answer

I figured it out its 1000m

anonymous · Answer

Our teacher gave us the answer which is 1.5 *10^-15N, but no matter what I do i just cant get this number

abb0t · Answer

Maybe your teacher is wrong then. But it should be ~1.5E-13

anonymous · Answer

What did you do to get the answer

abb0t · Answer

same thing ur teacher got, except to the -13 instead of -15.

anonymous · Answer

In the formula I plug in 1.67*10^-27 for the mass, 10 for the speed and 1000 for the radius but the answer i get is 1.67*10^-29. I don't know what I'm doing wrong

abb0t · Answer

It must be what you're typing in your calculator because I get 1.5...

anonymous · Answer

Do I have the correct numbers above?

abb0t · Answer

no

anonymous · Answer

Is the radius correct? 1000m

abb0t · Answer

yes.

anonymous · Answer

Would V equal 6283.18

abb0t · Answer

$$\frac{ (1.67 \times 10^{-27})(3 \times 10^8)^2 }{ 1000 }$$

anonymous · Answer

I probably was forgetting the parenthesis

anonymous · Answer

I put the parenthesis and got the answer.