Question

I tried to do it and i still dont get the answer. Please help. Consider the galvanic cell shown below (the contents of each half-cell are written beneath each compartment):
0.50 M Br2 0.20 M Cr3+
0.10 M Br–
The standard reduction potentials are as follows:
Cr3+ + 3e–  Cr(s) E° = –0.73 V
Br2(aq) + 2e–  2Br– E° = +1.09
What is the value of E for this cell at 25°C?

Answer 1

E^o is 1.82